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How can I define d/dx term in UDF?

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Old   June 17, 2021, 11:54
Default How can I define d/dx term in UDF?
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I would like to add the terms shown in picture below to each components of the momentum equation. Is there a way to define d/dx, d/dy and d/dz by using UDF macros? Also, if I achieve to do that does Fluent discretize and solve these terms just as it does other derivaives in momentum equation?

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Old   June 17, 2021, 13:42
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You're not showing terms, but an operator... What should this operate on?

(or maybe a better question to avoid follow up questions: can you write your momentum equation?)
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"The UDF library you are trying to load (libudf) is not compiled for parallel use on the current platform" is NOT the error after compiling. It is the error after loading. To see compiler errors, look at your screen after you click "build".
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Old   June 17, 2021, 14:10
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Quote:
Originally Posted by pakk View Post
You're not showing terms, but an operator... What should this operate on?

(or maybe a better question to avoid follow up questions: can you write your momentum equation?)


Actually I mean Mx d/dx, My d/dy and Mz d/dz as terms. There is nothing after derivatives (d/dx, d/dy, d/dz). Anyway here is the whole equation;


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Old   June 17, 2021, 16:50
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You say that there is nothing after the derivatives, but your equation shows that there is a vector B after the derivatives...

Is B the magnetic field? Fluent does not calculate the magnetic field (as far as I know), so you need to put in the magnetic field yourself. And taking the gradient of the magnetic field is an extra step that you have to do yourself also...
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