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Why the transient state initial velocity profile is not identical to the final steady |
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October 14, 2019, 07:27 |
Why the transient state initial velocity profile is not identical to the final steady
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#1 |
New Member
Ahmed
Join Date: Sep 2018
Location: Daejeon
Posts: 8
Rep Power: 8 |
I am studying flow in a 3D reactor which is rotating due to rotating disk present inside the reactor. Firstly, I simulated it with a steady-state RSM model and a converged solution has been obtained. Later on, I studied it with a Laminar transient state and initialized the flow field with the steady-state solution of RSM.
Now, when the transient state simulation is completed, I extracted velocity profiles at different time steps starting from the 0-time step (0 sec). To my understanding, the velocity profile of the 0-time step should be identical to the velocity profile obtained from RSM steady-state solution. But there is a slight difference in the velocity near the wall of a rotating disk. I am wondering why is that? I just checked the Solution Methods of both cases. In RSM, I used the SIMPLE scheme with the second order. While, in the Laminar transient state case, I used the PISO scheme with 1st order Momentum. So, are these changes resulting in different velocity values? I much appreciate if anyone could share his thoughts over it. Thanks in advance. |
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October 14, 2019, 13:51 |
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#2 |
Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
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RSM the turbulence model? If you run one with a turbulence model and one with a laminar model, of course the results will be different. Turbulent flows are different than laminar flows.
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October 15, 2019, 03:22 |
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#3 | |
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Ahmed
Join Date: Sep 2018
Location: Daejeon
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Quote:
You are right. Solver formulations are different from each other and there is no issue in getting different final results as I already got. But my question is "the initial Laminar transient solution should not be identical to the final steady RANS solution?" Since Laminar transient solver did not start solving it as I extracted result at 0 time-step. That is why I was hoping for the same results. In fact, they are same but differ in just two points near the wall of the rotating disk. Please correct me, if my understanding is wrong. |
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October 15, 2019, 10:04 |
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#4 |
Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
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Oh. My mistake, you mentioned a bunch of irrelevant details and fed me a red herring.
They should be identical, they could be identical. But it depends on what steps you used to "initialize" and "extracted." If it's the same mesh, then you shouldn't have to extract or initialize and there would've been a 1-to-1 correspondence. |
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October 16, 2019, 05:53 |
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#5 | |
New Member
Ahmed
Join Date: Sep 2018
Location: Daejeon
Posts: 8
Rep Power: 8 |
Quote:
However, the velocity profile is identical everywhere except near the rotating disk. Mesh is the same in both cases. I don't know why is that. Is it due to the friction of the rotating wall which hinders the fluid to flow near the wall? I initialized the solution in this way: File > Interpolate > write. |
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Tags |
laminar, rotating flow fluent, rsm, steady state solutionn, transient analisys |
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