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January 4, 2017, 05:25 |
Local Reynolds-Number?
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#1 |
New Member
Join Date: Oct 2016
Posts: 10
Rep Power: 9 |
Hey,
I need to compute Reynolds-Numbers in a turbulent flow. Assuming I got a 2D-flow and my domain is divided into squares, my question is how to compute the local Reynold-numbers. Imagine my domain is 1m x 1m and it is divided into 100x100 squares (each having a length of 1cm). Computing the global Reynolds-number (like in the OpenFOAM-Driven Cavity example) looks as follows: Re_global = rho*1m*U_inlet / nu. If I want to compute the local Reynolds-number for each square I consider 1cm instead of 1m but the remaining variables (rho,U,nu) stay the same, at least for incompressible flow. As a result, my local Re is only 1% of the global Re. But actually, it should be the same since the velocity, kinematic viscosity and density is the same in the whole 1m x 1m region. Can you tell me how to compute the local Reynolds-Number in such a flow so that it is an sufficiently accurate representation of the flow in the square? Thanks to all |
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Tags |
reynolds, turbulence |
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