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Can pressure do work in an incompressible flow?

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Old   January 15, 2018, 12:48
Default Can pressure do work in an incompressible flow?
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I am trying to analyze the energy equation for incompressible flows. I start with N-S and dot it with the velocity vector:

\bigg( \rho \frac{D\mathbf{u}}{Dt} - \nabla^2 \mathbf{u} + \nabla p \bigg) \cdot \mathbf{u} = 0

Then I get something like

1/2 \rho \frac{\partial \mathbf{u}^2}{\partial t} - \Phi + \mathbf{u}\cdot \nabla p = 0

I am interested in the work due to pressure term. Can this be nonzero if the flow is divergence free? Using identities it can be rewritten as

\mathbf{u} \cdot \nabla p = -p \nabla \cdot \mathbf{u} + \nabla \cdot (p\mathbf{u})

Obviously, the first term on the RHS is 0 if the flow is divergence free, but what is the second term? I am having trouble visualizing this one physically. When is it or isn't it equal to 0? I am having trouble understanding how pressure could do work on an incompressible flow. Any elucidation or thoughts would be very appreciated.
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