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iterations process for steady solver and time dependence for unsteady |
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#21 | |
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Filippo Maria Denaro
Join Date: Jul 2010
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Well I strongly advice the use of the integral of the kinetic energy into the whole domain. In a statistically steady state, you should have a balance between production and dissipation. Therefore, if the plot of the total kinetic energy in time shows that it oscillates around an average (constant in time) value, you can consider that the numerical transient is over. |
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#22 | |
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Serguei
Join Date: Mar 2015
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#23 | |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,813
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Not sure about what you are doing but if you are prescribing a constant temperature that means you let the heat flux to asses from the solution. Therefore you can have part of the region having heat entering into the domain and part leaving, insn't that? |
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iterations, steady, unsteady |
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