CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > General Forums > Main CFD Forum

CFD analysis on wind turbine rotor

Register Blogs Members List Search Today's Posts Mark Forums Read

Like Tree3Likes

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   March 31, 2011, 23:59
Default
  #41
Member
 
Naimish Harpal (MS Aerospace Engr)
Join Date: Jul 2009
Location: Long Beach, CA
Posts: 50
Rep Power: 17
naimishharpal is on a distinguished road
Thanks for sharing the technical papers.
mamyjooooon likes this.
naimishharpal is offline   Reply With Quote

Old   July 16, 2011, 07:12
Default New kind of turbine analyse in CFD
  #42
New Member
 
Marijan Pollak
Join Date: Jul 2011
Posts: 2
Rep Power: 0
Henrik14 is on a distinguished road
Hi everybody!
Now get this straight and at once: I am not mechanical engineer nor Physicist, so I do not know jargon, and I know only that CFD is technique for simulation of turbines (and whole WPS farms), since I am Systems Engineer and usually we get formulas prepared by someone else and are given examples of results to be able to check if program we made is working correctly or not.
Now I am in an awkward position, since I invented new kind of turbine for extracting the kinetic energy of wind, which is so different from all others that some formulas cannot apply, and I do not know exactly which ones I can use.
My turbine is different from others in one main aspect, and this is direction of wind flow. In all other turbines that I have studied, wind continue to move on same vector, usually slowed down after spending some of its kinetic energy on the blades/paddles or wings. in case of my turbine air exit on side, at 90 deg. angle to original wind flow. That mean that in original flow direction its speed is zero, and for such case Betz formula is not working/is giving wrong results.
Now before You all start telling me that I am wrong, I shall remind You why Betz Limit actually exist. Usually wind is slowed down on blades and such slowed down air becomes obstacle to next batch of wind that would pass trough has to spend good portion of its own energy to push this slower air downwind. Since in my turbine such air that passed turbine has exited on the side, then wind that has not entered the turbine but is flowing parallel to it is spending its energy to push such air downwind.
That means, in regard to wind that has entered turbine it would not count as unproductive spending of energy, so next batch is entering just as first.
Even if turbine would have 100% efficiency in extracting kinetic energy from wind and air on exit from turbine would have zero speed, it would present no problem since exit rotates and leaving zero speed air at one place, it moves and have new position to leave more zero speed air in path of original wind that bypass turbine, right?
But, my turbine is little more complicated than that.....
It is not slowing down air speed inside it, it is making it flow faster!
First part of turbine (cylindrical in shape) after entrance is funnel that act as air speeder like Venturi or Konfuzor, and with slopes at 30 degrees or less, drag should be non consequential, at least according to what I have read.
Wind is entering parallel to axle of rotation, and after passing the funnel has increased speed and reducted volume (therefore total energy remains the same) and from there it enters set of symetricaly positioned air chambers.
Simples turbine has just two air chambers, so turbine looks like an Savonius from top wiew, except in Savonius air enter from one side and other side causes drag, going againest the wind, where my turbine is round and rotates paralel to wind flow so there is no drag.
Those air chambers tapper in radial direction and have exit on their narrowest part which act as nozzle, expelling air almost tangential to turbine surface.
Effect is like it would be possible to channel all wind trough blades of standard turbine, to be left out at very tips in counter clockwise direction.
Air chambers also compress and speed up air which gain density as well, and in addition to this, I managed to harness also Centrifugal force which also speed up air in radial direction.
Air expelled trough nozzles produce reaction force and this turns turbine, so what is loss at other turbines (wind that pass trough turbine without contact with blades) is gain in my turbine.
You guess by now that such trurbine would present challenge even to CFD expert, which I am not, so I delegated CFD analyse to engineer that is making the prototypes since year 1996.
Unfortunately, he really has problem with getting results (using CFDdesign 3D) as he reported first that 90cm diameter turbine is making 2000 RPM at 200N on 1m stick as load, and thus producing 44 KW of power, with 5Km/hr or 1.39m/sec wind speed. Since I made small program that calculate energy input from turbine diameter and wind speed, I calculated that only 2.2 W has entered in form of kinetic energy so results were 20 000 times greater than possible. I concluded that mistake must be in decimal point of diameter, because in my country it is written as coma. If program ignored coma then diameter would be 100 times greater, and 100 squared is 10 000, right?
But he claims that diameter is in milimeters and that he input it correctly.
While I can explain energy gain of 200% if error was in size of turbine diameter, I know it is not possible to get that much greater result, it would be not even a miracle but totally impossible. Then he told me that somehow it was working with noncompresible flow, and that it has caused such results.
But now turbine act like it is using noncompressible flow as air do not want to enter it and at best in nozzles there is original wind speed achieved........
I know this is so because my small hand made model almost do not turn if put under the water flow, where it is rotating very fast on the wind of moderate speed.
Now with new parameter turbine turns 8-12.5 turns per minute, which is very slow for wind of 10m/sec. (36Km/hr), where in previous simulation it was turning as expected (for 90m diameter, that is).
So I am asking for help from all of you CFD experts, can You help me and my engineer coleague?
I would post some pictures from both simulations, but it is not possible here as page expect them to be at some WEB address and they are on my HD.....

Regards from Croatia, the Homeland of one of greatest inventors from 19th and 20th Centuries, Engineer Nikola Tesla!
Henrik14 is offline   Reply With Quote

Old   July 18, 2011, 23:11
Default WindSolars
  #43
New Member
 
Marijan Pollak
Join Date: Jul 2011
Posts: 2
Rep Power: 0
Henrik14 is on a distinguished road
Hi, Tortia.....
Well, it is simple question on which I cannot give simple answer, as it is both ""Yes" and "No" in both cases.
First, I am studying WPSs for at least 30 years, and I invented and reinvented several WPSs that I did not patent and some of them got stolen and patented by others.
Next I have company registered to do R&D for such things since 1993, but it is under blockade 6 years because of debts caused by my business Bank collapse, which put out of business all major client companies that declared insolvency and perished with about 65 thousand of others that were keeping money in that Bank.
I could have done the same since they took all of my "Liquid Assets", but vendors were also my friends, and if I would not pay their invoices, they would perish also.
One remaining vendor that was left unpaid was AMEX Company Card organization that froze my new Bank accounts and keep them frozen this precluding me to earn money I need for development of prototypes.
So figure out answer to Your questions by Yourself....
Without money to finance prototypes I cannot get investors , so only way to convince investors would be by presenting them with good CFD simulation results, but without m oneyI cannot buy required software and hardware, so I look for free CFD/FEA solver with perhaps CAD CAE included....

Thanks for suggestion, but my turbine has NO wings, blades or paddles, and so formulas mentioned do not apply, and inapplicable is BETZ Law also, because my turbine work on reactive principle and expell air faster than original wind speed trough its nozzles, using Venturi and Coanda effects, augumented by harnessed Centrifugal Force too.
Henrik14 is offline   Reply With Quote

Old   February 9, 2016, 14:16
Default when to stop iteration to get correct result.
  #44
New Member
 
pratik anand
Join Date: Feb 2016
Posts: 6
Rep Power: 10
panand01 is on a distinguished road
i am calculating drag force of moving vehicle for that i set BC and drag monitor for desired part then start iteration and i stop iteration in a regular time period and found different value of drag force at different iteration so,please give me idea when to stop iteration to got correct result.thanks for your suggestion.
panand01 is offline   Reply With Quote

Old   February 9, 2016, 14:48
Default
  #45
Senior Member
 
Shamoon Jamshed
Join Date: Apr 2009
Location: Karachi
Posts: 381
Rep Power: 18
Shamoon Jamshed is on a distinguished road
Send a message via Skype™ to Shamoon Jamshed
Apply the monitors for Drag, set your values and after (say 1000 iterations) plot the monitor file, if you see a cyclic variation over a period of certain iterations (lets say 500), take the mean of drag for this cyclic trend. If the values are constant then take them as it is. no need to take mean.
Shamoon Jamshed is offline   Reply With Quote

Old   February 9, 2016, 15:07
Default
  #46
New Member
 
pratik anand
Join Date: Feb 2016
Posts: 6
Rep Power: 10
panand01 is on a distinguished road
Quote:
Originally Posted by Shamoon Jamshed View Post
Apply the monitors for Drag, set your values and after (say 1000 iterations) plot the monitor file, if you see a cyclic variation over a period of certain iterations (lets say 500), take the mean of drag for this cyclic trend. If the values are constant then take them as it is. no need to take mean.
the fact is that ,the drag monitor (Cd) remain constant after 30 -35 iteration and continues as much as iteration taken and the value is
for iteration 80 , force approx 8000 and inlet -outlet mass =.3
for iteration 100, force approx 6000 and inlet -outlet mass =.002
for iteration 100, force approx 6000 and inlet -outlet mass =.002
for iteration 520, force approx 208 and inlet -outlet mass =.08
so i m confused
panand01 is offline   Reply With Quote

Reply

Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
Wind Turbine Analysis Suggestion andrea.pasquali OpenFOAM 13 March 25, 2015 06:27
CFX Analysis of a wind turbine Bournegenius CFX 16 August 20, 2012 20:16
ICEM CFD creating the grid of a Wind Turbine blade Dan CFX 11 June 1, 2012 15:11
Help Required on CFD for Turbine Blade Analysis kkjj2008 Main CFD Forum 5 July 9, 2009 16:41
Frozen Rotor and Wake of a Wind Turbine Peter CFX 0 June 26, 2006 16:12


All times are GMT -4. The time now is 13:28.