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June 26, 2017, 10:33 |
centrifugal pump simulation
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#1 |
New Member
Join Date: May 2017
Posts: 9
Rep Power: 9 |
Hi foamers
I have some questions about divSchemes , when I use MRFSimpleFoam to simulate the centrifugal pump . If I use below code ,I can simulate successfully. divSchemes { default none; div(phi,U) Gauss upwind; div(phi,k) Gauss upwind; div(phi,epsilon) Gauss upwind; div((nuEff*dev(T(grad(U))))) Gauss linear; } But if I use two order accuracy limitedLinear ,it will be divergent. divSchemes { default none; div(phi,U) Gauss limitedLinearV 1; div(phi,k) Gauss limitedLinear 1; div(phi,epsilon) Gauss limitedLinear 1; div((nuEff*dev(T(grad(U))))) Gauss linear; } My version of OpenFOAM is foam-extend-4.0. And its run log as follows,it only can run one step Create time Create mesh for time = 0 Initializing the GGI interpolator between master/shadow patches: GUIDE-OUTLET/IMPELLER-INLET Initializing the GGI interpolator between master/shadow patches: IMPELLER-OUTLET/VOLUTE-INLET SIMPLE: no convergence criteria found. Calculations will run for 1400 steps. Reading field p Reading field U Reading/calculating face flux field phi Selecting incompressible transport model Newtonian Selecting RAS turbulence model RNGkEpsilon RNGkEpsilonCoeffs { Cmu 0.0845; C1 1.42; C2 1.68; alphak 1.39; alphaEps 1.39; eta0 4.38; beta 0.012; sigmak 0.71942; sigmaEps 0.71942; } Creating MRF for cell zone IMPELLER. rpm = 2900 Excluded patches: 2(3 4) Starting time loop Time = 1 smoothSolver: Solving for Ux, Initial residual = 1, Final residual = 0.00436496, No Iterations 2 smoothSolver: Solving for Uy, Initial residual = 1, Final residual = 0.00451732, No Iterations 2 smoothSolver: Solving for Uz, Initial residual = 1, Final residual = 0.00450457, No Iterations 2 GAMG: Solving for p, Initial residual = 1, Final residual = 0.0359147, No Iterations 6 GAMG: Solving for p, Initial residual = 0.0362698, Final residual = 0.000442889, No Iterations 2 time step continuity errors : sum local = 5.86704, global = 0.471927, cumulative = 0.471927 smoothSolver: Solving for epsilon, Initial residual = 0.07982, Final residual = 0.000307204, No Iterations 2 bounding epsilon, min: -1.76856 max: 52.4243 average: 2.25425 smoothSolver: Solving for k, Initial residual = 1, Final residual = 0.00876813, No Iterations 2 ExecutionTime = 13.49 s ClockTime = 14 s Time = 2 smoothSolver: Solving for Ux, Initial residual = 0.168279, Final residual = 0.0013948, No Iterations 2 smoothSolver: Solving for Uy, Initial residual = 0.215064, Final residual = 0.00194542, No Iterations 2 smoothSolver: Solving for Uz, Initial residual = 0.185276, Final residual = 0.00162896, No Iterations 2 Please help me,thank you jack |
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