# setting nutilda boundary condition for LES

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 October 28, 2023, 05:32 setting nutilda boundary condition for LES #1 Senior Member   Saeed Jamshidi Join Date: Aug 2019 Posts: 213 Rep Power: 7 Hello, I'm going to adapt nutilda in 0 folder for my simulation, but I don't know how can I do it?! Although I'v read lots of materials about it, I couldn't reach a conclusion. there are various boundary types for nutilda, such as symmetry, fixedValue ... what is the type of nutilda for slip boundary??? please, provide me some information regarding this. Any ideas are welcome.

 October 28, 2023, 09:53 #2 Senior Member   Join Date: Apr 2020 Location: UK Posts: 640 Rep Power: 13 I am confused as to why you are talking about nutilda, i.e. the Spalart Allmaras model, for an LES simulation ... but as for your question: a slip boundary is the same as a symmetry plane (think about what the two conditions mean - they are equivalent). So just apply a symmetry boundary.

 October 28, 2023, 10:29 #3 Senior Member   Saeed Jamshidi Join Date: Aug 2019 Posts: 213 Rep Power: 7 Dear Tobermory, thank for the reply. I just want to run pitzdaily problem in the below tutorial: Code: `\\wsl.localhost\Ubuntu-18.04\home\myfoam\OpenFOAM\myfoam-v2112\run\tutorials\incompressible\pisoFoam\LES\pitzDaily\0` which nutilda was there by default. Besides, by searching among other tutorials I found zerogradient type for slip boundary condition. Here is the turbulence model turbulenceProperties: Code: ```/*--------------------------------*- C++ -*----------------------------------*\ | ========= | | | \\ / F ield | OpenFOAM: The Open Source CFD Toolbox | | \\ / O peration | Version: v2112 | | \\ / A nd | Website: www.openfoam.com | | \\/ M anipulation | | \*---------------------------------------------------------------------------*/ FoamFile { version 2.0; format ascii; class dictionary; object turbulenceProperties; } // * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * // simulationType LES; LES { LESModel dynamicKEqn; turbulence on; printCoeffs on; delta cubeRootVol; dynamicKEqnCoeffs { filter simple; } cubeRootVolCoeffs { deltaCoeff 1; } PrandtlCoeffs { delta cubeRootVol; cubeRootVolCoeffs { deltaCoeff 1; } smoothCoeffs { delta cubeRootVol; cubeRootVolCoeffs { deltaCoeff 1; } maxDeltaRatio 1.1; } Cdelta 0.158; } vanDriestCoeffs { delta cubeRootVol; cubeRootVolCoeffs { deltaCoeff 1; } smoothCoeffs { delta cubeRootVol; cubeRootVolCoeffs { deltaCoeff 1; } maxDeltaRatio 1.1; } Aplus 26; Cdelta 0.158; } smoothCoeffs { delta cubeRootVol; cubeRootVolCoeffs { deltaCoeff 1; } maxDeltaRatio 1.1; } } // ************************************************************************* //```

 October 28, 2023, 10:32 #4 Senior Member   Join Date: Apr 2020 Location: UK Posts: 640 Rep Power: 13 Yep - zeroGradient is the correct one - that gives a symmetry condition. saeed jamshidi likes this.