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[OpenFOAM-2.1.0] kklOmega RAS Turbulence Model (low Re) |
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#1 | |
Member
Join Date: Apr 2010
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Hello everybody.
As referenced in the announcement of the new release version of OpenFOAM a new turbulence model has been implemented: Quote:
Since I'm not an expert.... Is it an "automatic near wall teatment" (like the near wall treatment implemented in ANSYS CFX)?...then It resolves the viscous layer near the wall (mesh refinement is needed)? Thanks |
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#2 |
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Rui Vizinho de Oliveira
Join Date: Sep 2011
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Boas Alquimista (Or hi Alquimist
![]() I'm also going to begin using the transition model, I was also expecting to find some clarification about this in a tutorial or in any reference besides the one given in the openFoam site which is referencing an article of ASME. The thing is, I suspect that the boundary conditions for "kt" and "w" are similar to a regular k-w model, though the boundary conditions for kl, since it represents the laminar fluctuations kinematic energy should be set to zeroGradient at the walls , uniform zero in the domain (for initial conditions), fixed value uniform zero at the inlet and zeroGradient at outlet. My thoughts of course ![]() Best regards RuiVO |
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#3 |
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Klaus
Join Date: Mar 2009
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Hello Gentlemen,
let's join forces and setup a reference case using the kklomega model. How about a 2D case for a wing? I'd prefer a case based on a stl file so it can be adapted for different geometries. Interested? Klaus |
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#4 |
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Boas RuiVo (or Hola jejeje)
It's nice to see someone else interested in it. By now I needn't (or I can't) use this model since I realised that my case is fully turbulent but I'm interested on the results of the model. In my first topic I talked about the near wall treatment but I was wrong mixing the turbulence model itself with the boundary conditions specified for the wall treatment. I think it's a good idea suggested by klausb. I propose to use the object shown in the anouncement ![]() It would be nice to use a geometry present in some tutorial. I'm trying to find something appropiate. |
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#5 |
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Daniel WEI (老魏)
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Anyone knows how to set the boudndary condition for kl and kt?
For now I just copy k file and then rename to kl and kt. I am running a square case, and so far , the strouhal number, the mean and RMS value of force coeff look quite good!
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~ Daniel WEI ------------- Boeing Research & Technology - China Beijing, China |
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#6 |
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Klaus
Join Date: Mar 2009
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Hello,
would you mind sharing your case (post your case directory). I'd like to play with it over the weekend. Klaus |
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#7 |
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Simon Lapointe
Join Date: May 2009
Location: Québec, Qc, Canada
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According to the article presenting the model, you should use kl=kt=0 and omega =zeroGradient at walls. At the inlet, k=0 and kt and omega are similar to a k-w model so based on desired inlet turbulence intensity and viscosity ratio.
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#8 | |
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Daniel WEI (老魏)
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Quote:
But just for a future discussion. I have done a lot of tests, and generally I found kklOmega works well when it can work. But I found it do have convergence problems, especiall kl will grow very large within vortices. Relatively, I found other LRN models are more stable.
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~ Daniel WEI ------------- Boeing Research & Technology - China Beijing, China |
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#9 |
Senior Member
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I would vote for two test cases: 1) a classic zero-pressure gradient flat-plate boundary layer (Figs. 2-6 of Walters and Cokljat) and 2) S809 wind-turbine airfoil (Fig. 15-16 of Walters and Cokljat).
I have meshes for both, and will try to reproduce the results in this paper. If I am successful, I post case files. If not, I'll post questions and case file and we can work on this as a group. |
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#10 |
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Daniel WEI (老魏)
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And also a reminder, that I found the following utility is needed for using these kind of LRN turb model.
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~ Daniel WEI ------------- Boeing Research & Technology - China Beijing, China |
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#11 |
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Sandy Lee
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Yes, after my code skipped the time =0, it became convergent very well.
In addition, lakeat, you mean all LRN models can also solve transition flows (from laminar to turbulence), right? Last edited by sandy; January 21, 2012 at 01:36. |
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#12 |
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Daniel WEI (老魏)
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1. Turbulence;
2. (Re-)Attached or Separated Turbulence; And IMO, I think the three-equation model still needs extensive tests, and it needs to be bounded. (Chinese) 新年快乐!
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~ Daniel WEI ------------- Boeing Research & Technology - China Beijing, China |
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#13 |
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Sandy Lee
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Hi 老魏, 春节快乐!
![]() I want to find the model to simulation the transition flow, I guess kklomega model is good for it. However, you think, which scheme should be chose to bound the computation values? I find, in OF, almost all schemes are bounded schemes. What about your thought? Sandy Last edited by sandy; January 21, 2012 at 01:36. |
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#14 |
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Daniel WEI (老魏)
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Correction: I dont know if it really needs to be limited. I am struggling testing with some other convection schemes.
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~ Daniel WEI ------------- Boeing Research & Technology - China Beijing, China |
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#15 |
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Sandy Lee
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Yes, lakeat, except Guass upwind, I will change my code schemes into bounded schemes ...
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#16 | |
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I've set up the Schubauer and Klebanoff case for natural transition (as opposed to the ERCOFTAC bypass transition cases). I'm getting closer on getting kkLOmega to work, but the results still do not look good. Here is the Cf vs. Rex plot:
![]() You can download my case from here: http://dl.dropbox.com/u/2182201/kklOmega.tgz Note, freestream parameters are set as follows: U = 50.1 m/s Tu = 0.3 kt = 0.03388 m2/s2 kl = 0 m2/s2 nut/nu = 1 nu = 1.5e-5 m2/s omega = 2259 1/s wall boundary conditions are set to: kt = 0 m2/s2 kl = 0 m2/s2 omega = zeroGradient I'd be interested to see how others would try to set this case up. Quote:
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#17 | |
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OK, found a mistake in the 0/nut. wall b.c. for nut was incorrectly set from a fully turbulent case to nutWallFunction, and is now set to zeroGradient. This improves the solution, but laminar Cf and transition location are still off quite a bit.
![]() Quote:
Last edited by egp; January 23, 2012 at 09:16. |
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#18 |
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Sandy Lee
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Hi egp, I guess, you gave wrong the kt value. How did you calculate the kt and omega values?
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#19 | |
Senior Member
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Quote:
U=50.1 m/s Tu = 0.3% nut/nu = 1 Given these parameters, I compute kt and omega to be: kt = 1.5*(0.003*50.1)^2 = 0.0339 omega = k/nut = 0.0339/1.5e-5 = 2259 It's interesting to note that the paper by Walters and Cokljat (2008) did not use the S&K dataset for validation and only used the ERCOFTAC T3A-, T3A, T3B benchmarks. These latter cases have a varying degree of free-stream turbulence and are typically used to demonstrate bypass transition. In contrast, the S&K with low FST is more a test of natural transition. Last edited by egp; January 24, 2012 at 04:42. |
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#20 |
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Vincent RIVOLA
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Dear Eric,
Very interesting test case. did you try different mesh refinement to see if it has a large impact on the solution? spanwise and wall refinement? |
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