CFD Online Logo CFD Online URL
Home > Forums > Software User Forums > Phoenics

free surface

Register Blogs Members List Search Today's Posts Mark Forums Read

LinkBack Thread Tools Search this Thread Display Modes
Old   June 12, 2006, 12:30
Default free surface
Posts: n/a
In the free surface problem with SEM or HOL, What is the boundary conditions necessary (in the outlet) for a constant depth of water. <Cordially>
  Reply With Quote

Old   June 21, 2006, 01:52
Default free surface.
Gavin McSackdrop
Posts: n/a
hey. the gods mohummad give props to all those who provide free sutrfaces and gnesh will kill you if you dont. peace
  Reply With Quote

Old   May 18, 2010, 10:40
Default did you find your answer to this question?
New Member
Join Date: Jun 2009
Posts: 9
Rep Power: 16
R2DM is on a distinguished road
if so please let me know (email is sk2307 at
R2DM is offline   Reply With Quote

Old   September 10, 2012, 09:40
Default do you find the answer?
New Member
Join Date: Feb 2012
Posts: 3
Rep Power: 14
peiyuan is on a distinguished road
hey, if you find the answer, could you email me?
i meet difficulty in the similar problem. thank you.
peiyuan is offline   Reply With Quote


Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On

Similar Threads
Thread Thread Starter Forum Replies Last Post
Surface area of free surface jaswi OpenFOAM Post-Processing 0 July 25, 2007 14:34
surface tension gradient on a free surface Abrem FLUENT 1 April 30, 2006 03:41
free RANS code with free surface ability Lou jing Main CFD Forum 1 July 11, 2003 14:43
[surface tension effect at free-surface ?] name Main CFD Forum 1 September 21, 2001 09:54
Equilibrium of a free surface under surface tensio Ryan Main CFD Forum 1 August 7, 2001 16:14

All times are GMT -4. The time now is 12:35.