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Search: Posts Made By: FMDenaro
Forum: Main CFD Forum March 27, 2022, 07:11
Replies: 3
Views: 408
Posted By FMDenaro
That is very very simple, just use the...

That is very very simple, just use the Cartesian-Cilindrical representation

b = i bx + j by = ir br + itheta btheta


The tangential component is



b.itheta=(i bx + j by ).itheta
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