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Could symmetry BC cause relatively large residual? |
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January 30, 2015, 23:34 |
Could symmetry BC cause relatively large residual?
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#1 |
Senior Member
Meimei Wang
Join Date: Jul 2012
Posts: 494
Rep Power: 15 |
Hi,
I currently met a quite strange problem. When I run a simulation with a symmetry BC, I got relatively quite large residual (above 5e-5) near that symmetry BC. So I change the symmetry BC into free slip wall BC. Then the large residual disappears and the simulation converges to 1e-7. I used CFX for more than two years. That never happened before. Could anyone explain why this happens? Sorry that I can’t attach the CFX file here because it’s too large. Has anyone had the same experience or bring any hint?
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Best regards, Meimei |
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January 31, 2015, 04:36 |
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#2 |
Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,703
Rep Power: 143 |
A free slip wall and a symmetry boundary condition are mathematically similar, but not identical.
* They both have zero flow velocity across the boundary. * They both have zero shear stress for the tangential velocity component at the boundary But the symmetry boundary enforces zero normal gradient on all the scalars. The Slip wall does not do this. In a fully converged solution this should converge to the same result, but it does mean the symmetry boundary is more constraining and therefore can affect convergence. I would have thought a symmetry boundary would converge quicker than a slip wall - but you say you experienced the opposite. But I would think the number of cases where the difference between symmetry and free slip is important will be quite small. |
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