Heating Source

FrankW · February 17, 2021, 04:23

I have an electric resistance heater. First of all, I simply approximated this as an imprinted heat output. Unfortunately, I have found that there is probably a temperature dependency that cannot be neglected. Is there a simple way of making the impressed power dependent on the temperature?
I am currently using a subdomain with a heat source as a heater.

regards
Frank

evcelica · February 17, 2021, 14:50

Sure. Just make volumetric heat a function of temperature using the CFX expression language or a user function:
VolHeatExample = 100[W/m^3] + 5[W/m^3/K]*T.
You could also use an electric model, and have variable electrical resistance, and define a current or voltage on the conductor ends (see tutorials).

FrankW · February 18, 2021, 02:27

Thanks for the tip. I also came up with this type of solution yesterday. I wanted to avoid the electric model because of the effort involved.

February 17, 2021, 04:23	Heating Source	#1
FrankW Member Frank Weise Join Date: Mar 2009 Location: Germany Posts: 55 Rep Power: 17	I have an electric resistance heater. First of all, I simply approximated this as an imprinted heat output. Unfortunately, I have found that there is probably a temperature dependency that cannot be neglected. Is there a simple way of making the impressed power dependent on the temperature? I am currently using a subdomain with a heat source as a heater. regards Frank

February 17, 2021, 14:50		#2
evcelica Senior Member Erik Join Date: Feb 2011 Location: Earth (Land portion) Posts: 1,167 Rep Power: 23	Sure. Just make volumetric heat a function of temperature using the CFX expression language or a user function: VolHeatExample = 100[W/m^3] + 5[W/m^3/K]*T. You could also use an electric model, and have variable electrical resistance, and define a current or voltage on the conductor ends (see tutorials). aero_head likes this.

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February 18, 2021, 02:27		#3
FrankW Member Frank Weise Join Date: Mar 2009 Location: Germany Posts: 55 Rep Power: 17	Thanks for the tip. I also came up with this type of solution yesterday. I wanted to avoid the electric model because of the effort involved.