[Jwolf]

Hello

after reading some post not yet I know clearly some details to calculate these coefficient you formulate them in the CFX are:

Coeff Drag
force_x () @Tube wall/(0.5*Density*Area*Velocity^2)
Coeff Lift
force_z () @Tube wall/(0.5*Density*Area*Velocity^2)

Questions:

In post law that can be calculated coefficient with the pressure forces and viscosity in wall of the cylinder which they are obtained in file.out if I I use,

force_x () @Tube wall
force_y () @Tube wall
force_z () @Tube wall

it is just like to use the forces that are obtained in .out? according to what law in Help CFX. if.

The area is the reference area and it is obtained with the projection of the area in a cross flow plane to the direction of the flow, but equal it is not to me clear.

this area as one calculates for a cylinder located in perpendicularly to the direction of the flow? in three dimensions.

Diameter 0,01 m
length 0.2 m

also law that the depth has to do for cases 3D, but what is this depth?

http://img43.imageshack.us/img43/4125/cylinder3d.jpg (Dimensions cylinder)

thanks