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July 31, 2013, 13:24 |
Time in fluent
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#1 |
Senior Member
FHydro
Join Date: Jan 2013
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Hello
I am new in CFD and fluent. I am simulating a 2 meters long open channel with water velocity= 4 m/s. So in field or laboratory, every particle in flow cross into channel after 0.5 second. I am viewing flow after 0.5 second in fluent (the time that fluent shows), but flow does not yet arrive to outlet. My question is what the mean of time in fluent? Thanks |
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July 31, 2013, 13:40 |
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#2 |
Member
rayan
Join Date: Jun 2013
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Normally if your channel made 2m and your flow velocity equal to 4m/s so after 0.5s each fluid particle traveled the distance (d = 4m / s * 0.5s = 2m), so if the fluid does not reach the outlet after 0.5s I think it's just a problem of viewing no more!! tries to reduce the maximum value of velocity in the scale color. if the probleme is not resolved try to change your "time step" (maybe it is not enough)
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July 31, 2013, 14:31 |
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#3 | |
Senior Member
FHydro
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Quote:
I do not understand. The flow is in middle of channel but i have pressure and velocity and etc in downer than that point. Last edited by flow_CH; August 2, 2013 at 02:12. |
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July 31, 2013, 14:50 |
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#4 |
Member
rayan
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By a 3D visualization as you presented we can not draw conclusions .. try to present massqiue fraction and velocity on a one plane (just a plane)that intersects the inlet in the middle and through the channel..(The figures that you show are from a stationary simulation and not unsteady? non)
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July 31, 2013, 14:55 |
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#5 |
Senior Member
FHydro
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I will do that but this is unsteady simulation. Why you think this is steady?
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July 31, 2013, 15:18 |
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#6 |
Member
rayan
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It's just a feeling .. One question when you started the unsteady simulation, are you part of a solution that already exists? or just after defining your BC you cast the unsteady simulation??
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July 31, 2013, 15:28 |
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#7 |
Senior Member
FHydro
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After defining BCs and initialize and patch, i started unsteady simulation. what is your purpose?
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July 31, 2013, 16:03 |
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#8 |
Member
rayan
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oouh ..OK, I see where your problem comes!
So to make an unsteady simulation it is necessary to start with a solution already exists (ie its the solution at the initial time (t = 0)) |
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July 31, 2013, 16:13 |
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#9 |
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FHydro
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July 31, 2013, 16:51 |
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#10 |
Member
rayan
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The stationary solution converged well be your initial case (its the solution at t=0)
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August 1, 2013, 01:38 |
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#11 |
Senior Member
FHydro
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So you are saying first i should model in steady state then unsteady sate?( in the end of convergence i change steady to unsteady?)
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August 1, 2013, 03:28 |
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#12 |
Member
rayan
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Just when you get the convergence of steady state, you save this result then you use this result as the initial case (t=0) (not initialized your converged solution)
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August 1, 2013, 17:14 |
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#13 |
Member
rayan
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Is your problem has been solved?
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August 2, 2013, 00:54 |
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#14 |
Senior Member
FHydro
Join Date: Jan 2013
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Yes. But i have another problem.
I want to find p/gamma in model but the static pressures(p) are very large. I defined reference pressure location in top of water flow(where the air always exist). It is 101325 pa |
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August 2, 2013, 02:17 |
Water height
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#15 |
Senior Member
FHydro
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I want to find free surface height (Water height). I am plotting density for air and water(mixture) in a line. But in plot which density in closer to air i should choose for finding water height? (choosing (998) kg/s for water and (......) kg/s for interface between water and air)
Thanks |
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August 2, 2013, 03:47 |
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#16 |
Member
rayan
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Sorry but I did not understand your question
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August 2, 2013, 04:16 |
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#17 |
Senior Member
FHydro
Join Date: Jan 2013
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Just i want to find Water height in channel (from bottom of channel to free surface)
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August 2, 2013, 04:19 |
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#18 |
Member
rayan
Join Date: Jun 2013
Posts: 65
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Normalement la hauteur d'eau c'est toi qui le définit en se basant sur la visuatlisation de ta simulation!
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