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#1 |
New Member
Andrew
Join Date: Dec 2022
Posts: 29
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A simple clarification question -
In a 2D axisymmetric case, the x-axis is the axis of symmetry. Then, applying gravity in the +x or -x direction simulates a vertically-oriented tube (gravity acts axially). Does y-directed gravity then simulate a horizontally-oriented tube? (This makes the most sense to me, but then the domain is not exactly symmetric). Or, would it simulate a tube with gravity always directed radially/towards the center? (This would preserve symmetry, but I can't imagine why this would be useful). If anyone can confirm that y-directed gravity in 2D axisymmetric case simulates a horizontally-oriented tube, I'd greatly appreciate it. Thanks! |
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#2 |
New Member
Alan
Join Date: Dec 2021
Posts: 9
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Fluent requires that the axis of symmetry is on the x-axis. In this case, no fluid can cross the symmetry axis, and no fluid is expected to move in the tangential direction. Therefore the gravity expressed in the y-direction would be the same as expressing it in the radial direction and is not the same as simulating a horizontally oriented tube.
If your problem contains just one phase, check if gravity can be neglected. If gravity is important, do a 3D simulation. |
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#3 |
New Member
Join Date: Jan 2025
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i have a quastion now
i simulating a vertical pipe that flow go in from top and go out from botton in aximmetric i must draw it horizontal in this case flow go in from left and go out from right so my quastion is i must put gravity +9.8 or -9.8? Untitled.jpg |
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#4 |
New Member
Alan
Join Date: Dec 2021
Posts: 9
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If fluid flows from top to bottom (parallel to the gravity vector), when simulating, the fluid vector points in the positive direction of the x-axis; therefore, you should set the gravity vector pointing in the positive x-direction.
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Tags |
axial, axisymmetric, gravity, tube |
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