
[Sponsors] 
October 11, 2011, 04:55 
some problem in the UDS

#1 
New Member
YuPei Chen
Join Date: Jun 2011
Posts: 26
Rep Power: 7 
hi, everybody, I create a UDS as follow : d(phi)/dt=m, where phi is scalar variable, and m is my source term : m = C*exp(E/RT)*log(p/p_eq)*(Dphi), where C, E, R and D are constant, T is temperature, p is pressure and p_eq is equilibrium pressure (function of temperature). I wrote a udf code below :
================================================== ======= #include "udf.h" #include "mem.h" #include "math.h" #include "stdio.h" #define R 8.314 #define E 21180 #define C 59.19 #define SAT_DEN 7259 #define A 17.61 #define B 3704.6 DEFINE_ADJUST(absorption,d) { Thread *t; cell_t c ; real p_g ; real P_eq; real m ; thread_loop_c(t,d) { begin_c_loop(c,t) { real tem = C_T(c,t) ; p = C_P(c,t)+101325; p_eq= 1000*exp(A(B/tem)); m = C*exp(E/R*tem)*log(p/p_eq); C_UDMI(c,t,0) = m ; } end_c_loop(c,t) } } DEFINE_SOURCE(uds_source,c,t,dS,eqn) { real source ; source = C_UDMI(c,t,0)*(SAT_DENC_UDSI(c,t,0)); return source ; } ================================================== ===== my problem is when I simulate the UDS with CE, ME and EE, the result is not good, because the phi's distribution is very uniform, but I expect its distribttion are respect to the location, it should not be uniform, can anybody help me ? thank you ! 

October 11, 2011, 05:27 

#2 
Senior Member

Hi,
1 your source term is a function of UDS, so you can define it's derivation with respect to your UDS to enhance stability. 2 Did you disable convective term of UDS equation while activation? 3 Did you set diffusion coefficient to zero? 4 According to UDS equation, the phi variable would be ; which C is your UDS; if your base fluid density is not equal to 1, you have to change your source equation respectively. (BC should be changed) Bests,
__________________
Amir 

October 11, 2011, 09:24 

#3 
New Member
YuPei Chen
Join Date: Jun 2011
Posts: 26
Rep Power: 7 
hi, thank for your reply, Amir
1 your source term is a function of UDS, so you can define it's derivation with respect to your UDS to enhance stability. Ok , I'll try . 2 Did you disable convective term of UDS equation while activation? yes, I set it to be "none" in the panel. 3 Did you set diffusion coefficient to zero? yes, in the Material setting. 4 According to UDS equation, the phi variable would be ; which C is your UDS; if your base fluid density is not equal to 1, you have to change your source equation respectively. (BC should be changed) I use the macro "DEFINE_UDS_UNSTEADY" to set the unsteady term, and let the rho equal to 1. my simulation can run when the udf code is used, but the result seems not good .... 

October 11, 2011, 15:51 

#4 
Senior Member

Ok, it doesn't need any other special settings; it can be implied form results that your source term is large! Maybe its better to check dimension of constants ....
Bests,
__________________
Amir 

October 11, 2011, 22:00 

#5 
New Member
YuPei Chen
Join Date: Jun 2011
Posts: 26
Rep Power: 7 
Thank you, Amir. I will keep checking my code.


Thread Tools  
Display Modes  


Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
UDS problem with wall boundary condition  Alex F.  FLUENT  15  September 21, 2015 09:28 
Velocity profiles problem behind the elbow (3D problem)  kabat73  FLUENT  8  May 9, 2010 04:26 
natural convection problem for a CHT problem  SeHee  CFX  2  June 10, 2007 06:29 
Adiabatic and Rotating wall (Convection problem)  ParodDav  CFX  5  April 29, 2007 19:13 
Is this problem well posed?  Thomas P. Abraham  Main CFD Forum  5  September 8, 1999 14:52 