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August 9, 2006, 11:48 |
Mean Free Path of water vapor?
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#1 |
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Can anyone tell me the mean free path of water vapor at 293.15K, and partial vapor pressure of 0.023062atm ?
(Remember that at 293.15K, P_vapor = 0.023062 atmospheres and P_air = 0.976938 atmospheres is the saturation condition, i.e. 100% Relative Humidity.) |
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