CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > General Forums > Main CFD Forum

spectrum tensor in inhomogeneous turbulence

Register Blogs Community New Posts Updated Threads Search

Like Tree3Likes
  • 1 Post By Santiago
  • 1 Post By FMDenaro
  • 1 Post By FMDenaro

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   May 27, 2019, 11:35
Default spectrum tensor in inhomogeneous turbulence
  #1
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Hi all,
I am trying to write the theory of the energy spectrum for a generic inhomogeneous turbulence. I used as a basis for my work the tennekes and lumley book. I attached here the page of this book and I tried to rewrite the spectrum tensor for inhomogeneous turbulence.

Can someone confirm that I did it well? My doubt is the fact that in the exp() there is no x vector and I am wandering if I am missing something.

I really hope that someone can help me
Attached Images
File Type: png inhomogeneous case.PNG (26.8 KB, 26 views)
lucamirtanini is offline   Reply With Quote

Old   May 29, 2019, 15:08
Default
  #2
Senior Member
 
Santiago Lopez Castano
Join Date: Nov 2012
Posts: 354
Rep Power: 15
Santiago is on a distinguished road
Quote:
Originally Posted by lucamirtanini View Post
Hi all,
I am trying to write the theory of the energy spectrum for a generic inhomogeneous turbulence. I used as a basis for my work the tennekes and lumley book. I attached here the page of this book and I tried to rewrite the spectrum tensor for inhomogeneous turbulence.

Can someone confirm that I did it well? My doubt is the fact that in the exp() there is no x vector and I am wandering if I am missing something.

I really hope that someone can help me
Because the integration is made for a "ball", hence the radius r. That operator is quite tricky to implement, specially when you come close to a boundary. Besides, is not common to consider the cross correlations in spectral analysis... the diagonal terms have direct physical meaning in spectral space
lucamirtanini likes this.
Santiago is offline   Reply With Quote

Old   May 30, 2019, 03:51
Default
  #3
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,773
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by lucamirtanini View Post
Hi all,
I am trying to write the theory of the energy spectrum for a generic inhomogeneous turbulence. I used as a basis for my work the tennekes and lumley book. I attached here the page of this book and I tried to rewrite the spectrum tensor for inhomogeneous turbulence.

Can someone confirm that I did it well? My doubt is the fact that in the exp() there is no x vector and I am wandering if I am missing something.

I really hope that someone can help me



I am not sure of what exactly want to do. If you consider a fully 3d non-homogenous non-isotropic turbulence, it could be also questioned how do you define the Fourier analysis since it is not a periodic function.
From the general definition you wrote, there is more that the fact your function depends on the position x. The problem is also in the extension of the integrals.


I can say that in a practical case like the flow in a plane channel, where we have two homogeneous dimensions and one (normal to the wall) non-homogeneous dimension, we perform the 1D spectra along the directions of homogeneity. And these spectra are evaluated for several positions along the non-homogenous direction.
lucamirtanini likes this.
FMDenaro is offline   Reply With Quote

Old   May 30, 2019, 10:48
Default
  #4
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by Santiago View Post
Because the integration is made for a "ball", hence the radius r. That operator is quite tricky to implement, specially when you come close to a boundary.
In the step of the demonstration that I have shown there is no integration on the radius.

Quote:
Originally Posted by Santiago View Post
Besides, is not common to consider the cross correlations in spectral analysis... the diagonal terms have direct physical meaning in spectral space
I will not use this formula directly in a calculation. I was trying to generalize the demonstration fora a 3d inhomogeneous turbulence.
lucamirtanini is offline   Reply With Quote

Old   May 30, 2019, 10:56
Default
  #5
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
I am not sure of what exactly want to do. If you consider a fully 3d non-homogenous non-isotropic turbulence, it could be also questioned how do you define the Fourier analysis since it is not a periodic function.
I do not see a linke between the fact of being a 3d inhomogeneous turbulnence and the use of the fourier analysis.

Quote:
Originally Posted by FMDenaro View Post
From the general definition you wrote, there is more that the fact your function depends on the position x. The problem is also in the extension of the integrals.


I can say that in a practical case like the flow in a plane channel, where we have two homogeneous dimensions and one (normal to the wall) non-homogeneous dimension, we perform the 1D spectra along the directions of homogeneity. And these spectra are evaluated for several positions along the non-homogenous direction.
In my opinion, the extension of the integral is not the problem, since it is a generic demonstration.
lucamirtanini is offline   Reply With Quote

Old   May 30, 2019, 11:16
Default
  #6
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,773
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
https://ntrs.nasa.gov/search.jsp?R=19790022816
lucamirtanini likes this.
FMDenaro is offline   Reply With Quote

Old   May 30, 2019, 11:30
Default
  #7
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
Thank you. I have already read this one. He wrote the formula like I did, but the formula 1.7 seems to me to be wrong since there is not the (1/2pi)^3. Do you agree?
lucamirtanini is offline   Reply With Quote

Old   May 30, 2019, 11:38
Default
  #8
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,773
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by lucamirtanini View Post
Thank you. I have already read this one. He wrote the formula like I did, but the formula 1.7 seems to me to be wrong since there is not the (1/2pi)^3. Do you agree?

If you see the 1.8, the factor appears in the correlation function
FMDenaro is offline   Reply With Quote

Old   May 30, 2019, 11:41
Default
  #9
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Yes, but it should have been placed also in the 1.7. Isn't it?
lucamirtanini is offline   Reply With Quote

Old   May 30, 2019, 11:47
Default
  #10
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,773
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by lucamirtanini View Post
Yes, but it should have been placed also in the 1.7. Isn't it?



No, correlation and spectra are a Fourier pair transform, for example here you see the factor in the spectra but not in the correlation
https://www.google.com/url?sa=t&rct=...VEGq8lnm20jOIu
FMDenaro is offline   Reply With Quote

Old   May 30, 2019, 11:54
Default
  #11
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
No, correlation and spectra are a Fourier pair transform, for example here you see the factor in the spectra but not in the correlation
https://www.google.com/url?sa=t&rct=...VEGq8lnm20jOIu

No, if you look at the page of the tenneke and lumley book that I have shown in the first post. You can see that the psi in the paper is the phi in the book of lumley, and the Cij in the paper is the Rij in the book of Lumley. So the (1/2pi)^3 is missing
lucamirtanini is offline   Reply With Quote

Old   May 30, 2019, 13:16
Default
  #12
Senior Member
 
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,675
Rep Power: 66
LuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura about
Quote:
Originally Posted by lucamirtanini View Post
No, if you look at the page of the tenneke and lumley book that I have shown in the first post. You can see that the psi in the paper is the phi in the book of lumley, and the Cij in the paper is the Rij in the book of Lumley. So the (1/2pi)^3 is missing

They have different definitions for the Fourier transform and that's why you see the 2pi in different places.


Or am I misunderstanding the question?
LuckyTran is offline   Reply With Quote

Old   May 30, 2019, 15:41
Default
  #13
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by LuckyTran View Post
They have different definitions for the Fourier transform and that's why you see the 2pi in different places.


Or am I misunderstanding the question?
Sorry for the stupid question, what does it means that they have different definitions for the F T? Which definition of FT is used by Trevino and which one is used by Lumley and Tennekes?
lucamirtanini is offline   Reply With Quote

Old   May 31, 2019, 10:15
Default
  #14
Senior Member
 
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,675
Rep Power: 66
LuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura aboutLuckyTran has a spectacular aura about
Lumley is using the one with the 1/(2pi) and Trevino is using the one with 1 as the prefactor.
LuckyTran is offline   Reply With Quote

Old   May 31, 2019, 11:02
Default
  #15
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by LuckyTran View Post
Lumley is using the one with the 1/(2pi) and Trevino is using the one with 1 as the prefactor.
Ok...I am not enough expert of FT. How can they be equivalent? Is the 1/(2pi) included in the correlation coefficient in the trevino paper?
lucamirtanini is offline   Reply With Quote

Old   May 31, 2019, 12:49
Default
  #16
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,773
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by lucamirtanini View Post
Ok...I am not enough expert of FT. How can they be equivalent? Is the 1/(2pi) included in the correlation coefficient in the trevino paper?



Have a look to pag 220 of the Pope's textbook, you see the factor (2pi)^3 in the spectrum but not in the correlation. They constitute a Fourier transform pair. The Fourier transform has the factor 2*pi, the inverse transform has not, see Appendix A (pag 678). You will read the explicit statement about the fact that this factor is sometimes interchanged between direct and inverse transform.


Let me say that I often observed similar notations that drive people to some misleading reading, for example the Fourier decomposition in components along wavenumbers k=n*2pi/L where L is the length of periodicity. When sometimes is assumed L=2*pi, the factor 2*pi disappears and k=n. But n is the wavenumber while k is the dimensional frequency.
FMDenaro is offline   Reply With Quote

Old   June 1, 2019, 05:33
Default
  #17
Senior Member
 
luca mirtanini
Join Date: Apr 2018
Posts: 165
Rep Power: 8
lucamirtanini is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
Have a look to pag 220 of the Pope's textbook, you see the factor (2pi)^3 in the spectrum but not in the correlation. They constitute a Fourier transform pair. The Fourier transform has the factor 2*pi, the inverse transform has not, see Appendix A (pag 678). You will read the explicit statement about the fact that this factor is sometimes interchanged between direct and inverse transform.


Let me say that I often observed similar notations that drive people to some misleading reading, for example the Fourier decomposition in components along wavenumbers k=n*2pi/L where L is the length of periodicity. When sometimes is assumed L=2*pi, the factor 2*pi disappears and k=n. But n is the wavenumber while k is the dimensional frequency.
If you look carefully at the trevino paper you will see that the equations 1.7 and 1.8 are not fourier transform pairs. So the factor could not be introduced in 1.8. If there was a definition of Cij as an inverse fourier transform of psi, than I can understand your statement
lucamirtanini is offline   Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
how to set URANS turbulence model in unsteady flow simulation TimLiu OpenFOAM Pre-Processing 0 April 25, 2017 08:52
Simulation FPEs - turbulence for transient and steady-state? DaveR OpenFOAM Running, Solving & CFD 5 March 5, 2017 15:06
Turbulence postprocessing Mohsin FLUENT 2 October 3, 2016 14:18
turbulence spectrum niaz Main CFD Forum 0 February 28, 2012 01:04
turbulence modeling questions llowen Main CFD Forum 3 September 11, 1998 04:24


All times are GMT -4. The time now is 20:39.