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Differences between production term in k-epsilon!

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Old   May 13, 2024, 13:12
Exclamation Differences between production term in k-epsilon!
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Tom Waits
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Reading about the production term for k-epsilon here:
https://www.cfd-online.com/Wiki/Stan...-epsilon_model
it is given as
P_k=2\mu_t S_{ij}S_{ij}


but on the NASA website here:
https://turbmodels.larc.nasa.gov/ke-chien.html
a much more complicated form is given as:
P=\tau_{ij}\frac{du_i}{dx_j}

where
\tau_{ij}=\mu_t(2S_{ij}-2/3\frac{du_k}{dx_k}\delta_{ij})-2/3\rho k\delta_{ij}



I have coded both up and get slightly different results for the production term in my k-epsilon model! Where do these two forms come from and why are they different?


Many thanks in advance,
Tom Waits
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Old   May 15, 2024, 07:03
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Quote:
Originally Posted by TomWaits View Post
Reading about the production term for k-epsilon here:
https://www.cfd-online.com/Wiki/Stan...-epsilon_model
it is given as
P_k=2\mu_t S_{ij}S_{ij}


but on the NASA website here:
https://turbmodels.larc.nasa.gov/ke-chien.html
a much more complicated form is given as:
P=\tau_{ij}\frac{du_i}{dx_j}

where
\tau_{ij}=\mu_t(2S_{ij}-2/3\frac{du_k}{dx_k}\delta_{ij})-2/3\rho k\delta_{ij}



I have coded both up and get slightly different results for the production term in my k-epsilon model! Where do these two forms come from and why are they different?


Many thanks in advance,
Tom Waits
The second one is the only correct form of the production term in k equation. The first one is, nonetheless, a very common approximation (fully correct only for soleinodal velocity fields).

The approximation is certainly more stable, that's one of the reasons it got large acceptance.
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Old   May 15, 2024, 08:26
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Filippo Maria Denaro
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The isotropic terms could be absorbed by the “pressure”
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