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Old   May 18, 2001, 18:25
Default Anybody can help with DFFT?
  #1
Wen Long
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Hi, friends:

I have a question on Discrete FFT, it dogged me a whole day.

I was trying to use pseudospectral method to solve a kdv equation as:

du/dt+u*du/dx +d^3u/dx^3=0

where 0<x<L

The domain [0,L] is discreted in to N points, N is power of 2,say N=1024. Then the FFT of u is

FFT(u)=U(k)=SIGMA(u(j)*exp(-2pi*i*j*k/N),j=0,...,N-1)

where k=0,...,N-1, i=sqrt(-1) This is ok, but to do the du/dx term, I used the following formular:

du/dx=IFFT(k*i*FFT(u))

I let u=sin(2pi*x/32), put it into the upper equation, the results is the same form as cos(2pi*x/32), which is expected, but the magnitude is wrong. The corrected answer should be (2pi/32)cos(2pi*x/32).

I think I must have doing something wrong in scaling. I looked some references, but can't find the problem, the FFT() routine I used is standard and should not have problems. What people usually do is scaling the domain [0,L] to [0,2pi], what's the point that they do so? I just want use FFT on the domain [0,L]. Can this cause problems?

Thank you very much if you can point it out.

Wen

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Old   May 21, 2001, 15:32
Default Re: Anybody can help with DFFT?
  #2
Patrick Godon
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The FFT is for an angle that goes from 0 to 2 pi, so you better scale your problem accordingly.

O to 2 pi is periodic of period 2 pi. So your problem should also be periodic on the domain 0, L, of period L (otherwise you'll get the famous Gibbs oscillations; divergence of the Fourier series).

Why don't you like to work from 0 to 2pi?

Cheers.
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