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March 5, 2002, 20:05 
Please help a newbie find the drag on a 3d model

#1 
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By poly i mean a plane with a definate area, if you know what i mean. What i thought was: the force reaction from the "wind" on the poly is 0.5(p(V^2)S) = Force Where p=Air density V=Velosity of wind s=Surcace area of poly ^=to the power of Would i be correct in thinking that to find out the force against a poly that wasnt directly facing the wind i would just multiply the result from the last equation by cos(theta) where theta is the angle between the normal of the poly and the direction of the wind. I know there are many other factors invloved such as the deflection of wind form the rest of the model changing the direction of the wind on each poly, heat generated, etc..., etc. but is what i have worked out so far correct. if what i have worked out so far is good i could manage the shading bit my self. Any help would be greatly appresiated. thanks. 

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March 6, 2002, 04:33 
Re: Please help a newbie find the drag on a 3d mod

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For each poly, the Pressure Drag Force (PDF) vector is equal to P.N where N is the normal to the so call poly with N = S and P is the pressure (scalar).
You also have a Skin Friction Drag Force (FDF) vector which can be compute if you know the deformation D (tensor) at the skin of your model by 2.mu.D.N. the dimesionless drag coefficient Cd is defined by : Cd = (PDF*i+FDF*i)/(0.5*rho*V^2*S) if i is the unity vector align with the flow direction, rho is the air density and V is the flow velocity. This drag coefficient is usefull if you want to compare the aerodynamic design of several cars. From Hucho's book, this drag coefficient is equal to 1.17 for a circular plate, 0.47 for a sphere, 0.42 for half a sphere. This 3 shapes are view as a disc by the flow. Sylvain 

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