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October 31, 2011, 23:55 
Question about Continuous Adjoint Method

#1 
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Fumiya Nozaki
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Hi,
I'm studying the "continuous" adjoint method by reading Dr.Soto's article titled "ON THE COMPUTATION OF FLOW SENSITIVITIES FROM BOUNDARY INTEGRALS". http://www.scs.gmu.edu/~rlohner/page.../reno04adj.pdf I have a question regarding this article. Could someone answer the following question? Q)Question about the derivation of the adjoint boundary conditions My understanding is that the adjoint boundary conditions are derived so that all the boundary terms of equation (13) are exactly canceled at all boundaries. I think we need the value of δu and δp at boundaries when deriving the conditions. Could you tell me how to know these values? It says in this article that "δu=0 on S and on the outflow (Γout)(δu is the test function associated to the adjoint velocity, then it is zero wherever ψu is prescribed)" but I can't understand the meaning of this description at all. Thanks. 

November 1, 2011, 00:26 

#2 
Super Moderator

If on some part of boundary, u is fixed by the boundary condition, then du=0 on that part.
If u is not specified on some part S of boundary, and you have a term like int(S)(X du) then set X=0 on S. The idea is simply to get rid of all the variations in the primal quantities. 

November 1, 2011, 01:50 

#3 
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Fumiya Nozaki
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Thanks for reply. I understand your comment.
It says in this article that "δu=0 on S(solid boundaries to be optimized) and on the outflow (Γout)". I think that δu=0 is valid on S because of the dirichlet (noslip) boundary condition but I can't understand why δu=0 on the outlet boundary. I think dirichlet conditions are not imposed on the velocity at the outlet when solving the flow. Q) Is δu=0 valid on the outlet boundary? I have another question. Q) Could someone understand the meaning of the following statement? "δu is the test function associated to the adjoint velocity, then it is zero wherever ψu(adjoint velocity) is prescribed" 

November 1, 2011, 03:41 

#6 
Super Moderator

On outflow boundary, u must come from the solution, it is not prescribed. Hence we dont know du. So to get rid of du on outflow boundary, set Psi_u=0. Thats how I look at it.


November 1, 2011, 11:09 

#7 
Senior Member
Fumiya Nozaki
Join Date: Jun 2010
Location: Yokohama, Japan
Posts: 200
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Could someone tell me why the following statement is valid?
"δu is the test function associated to the adjoint velocity, then it is zero wherever ψu(adjoint velocity) is prescribed" 

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