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power of vectorField

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Old   August 19, 2014, 08:52
Default power of vectorField
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Matthias Walter
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Hi,

I need the element-wise power of a vectorField (or a volVectorField), e.g.

vectorField V;
pow(V, 0.7)

with pow(V.X(), 0.7) , pow(V.Y(), 0.7) and pow(V.Z(), 0.7).

A possible way could be to use the component method as

Code:
scalarField x = pow(V.component(vector:X), 0.7);
scalarField y = pow(V.component(vector:Y), 0.7);
scalarField z = pow(V.component(vector:Z), 0.7);
and to create a new vector Field and to set the single components

Code:
vectorField tmp = x*vector(0,0,0);

tmp.component(0) = x;
tmp.component(1) = y;
tmp.component(2) = z;

All in all, it is working but I think there must be a better way to do that or has OF already such function?

Best regards

Matthias
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