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November 24, 2015, 07:35 |
Mathematic expression of grad(U)
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Tobias Holzmann
Join Date: Oct 2010
Location: Tussenhausen
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Hi all,
I have just one question. In mostly all literature we find the gradient of a scalar or vector in that way. But in a mathematic point of view this is not correct for vectors. So we get for any scalar: Of course I assume as the partial differentials of the three directions and this is correct but For any vector: My question now. Is it just a definition that we suppose that everybody know that is the transposed dyadic product of these two vectors? Because normally, and are two vectors with the matrix notation (3x1) and (3x1). Therefore we have to use the dyadic product of this operation and after that we really have to transpose that matrix to get the correct form of the gradient matrix. Example: Again. Is it a definition that in CFD numerics we say: I would kindly appreciate some feedback.
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Keep foaming, Tobias Holzmann Last edited by Tobi; November 24, 2015 at 11:36. |
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