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Initial Perturbation of Interface in Rayleigh-Taylor Instability |
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October 10, 2017, 10:49 |
Initial Perturbation of Interface in Rayleigh-Taylor Instability
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I am using buoyantPimpleFoam to simulate Rayleigh-Taylor instability of air with a hot gas on the lower portion of the domain (T = 900 K) and cold air on top (T = 300 K). Pressure being 101.325 kPa and g = (0,-9.81,0) m/s^2. I originally tried to perturb the interface by a simple cosine function f(x) = 0.05/2*(1+cos(2*pi*x)), but the mesh resolution created a "stair step" situation where the small steps acted as artificial perturbation surfaces.
https://imgur.com/TP0rx7R https://imgur.com/mXQDZGI This a short video of how the "stair stepping" forces the flow to behave: https://imgur.com/TP0rx7R I tried running this at a finer resolution, but the behavior is still the same and becomes economically less practical as you refine this more and more. My next attempt was to apply a perturbation to the y-velocity instead. The idea being that the baroclinic vorticity generation (cause of the RT growth) occurs across the density gradient, thus any "stair stepping" would cause instability growth. Thus as long as the density interface is flat, then the above problems would not be present. The perturbation velocity would then force small fluid motion leading to interface movement without the effects of the mesh present. I did this via the following function: Vy = 0.01/4*(1+cos(2*pi*x))*(1+cos(100*pi*y)) But when I ran this for over a second, the interface had not moved even a little bit. I'm not quite sure why the above didn't work. Is there a different way to perturb the interface in OpenFoam that would avoid the mesh issue? And if my solution is the correct method, then why was I not able to get fluid motion? |
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Tags |
buoyantpimplefoam, instability, rayleigh, rayleigh-taylor, taylor |
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