pimpleFoam - lower nonzero limit for the production term in k transport equation

cyln · April 12, 2018, 03:27

Hello,

I am running a transient turbulent simulation using pimpleFoam. The turbulence model is k-omega-SST.

I am trying to make sure the solver does not impose a lower nonzero limit for the production term in k transport equation. When I set k to machine zero (meaning eddy viscosity = 0), the production term should go to zero.

I do this to obtain a laminar boundary layer development in a specific region of my computational domain.

Can anybody illuminate me on this issue?

Cheers,
Cyln

TobM · April 12, 2018, 04:34

In the omega equation in kOmega.C one term is devided by k.
This is the reason why the minimum of k is SMALL.

April 12, 2018, 03:27	pimpleFoam - lower nonzero limit for the production term in k transport equation	#1
cyln Senior Member cyln Join Date: Jul 2016 Posts: 102 Rep Power: 9	Hello, I am running a transient turbulent simulation using pimpleFoam. The turbulence model is k-omega-SST. I am trying to make sure the solver does not impose a lower nonzero limit for the production term in k transport equation. When I set k to machine zero (meaning eddy viscosity = 0), the production term should go to zero. I do this to obtain a laminar boundary layer development in a specific region of my computational domain. Can anybody illuminate me on this issue? Cheers, Cyln

Similar Threads
Thread	Thread Starter	Forum	Replies	Last Post
Calculation of the Governing Equations	Mihail	CFX	7	September 7, 2014 06:27
ATTENTION! Reliability problems in CFX 5.7	Joseph	CFX	14	April 20, 2010 15:45
Is it possible to use divergence in the source term of an scalar transport equation?	jannnesss	CFX	0	January 8, 2010 19:53
Turbulent Heat Transfer Transport Equation	Flo.duck	Main CFD Forum	0	May 6, 2009 03:37
bouyancy term in epsilon equation	Michael	Main CFD Forum	1	June 25, 1999 10:20

April 12, 2018, 04:34		#2
TobM Member Join Date: Sep 2014 Location: Germany Posts: 88 Rep Power: 11	In the omega equation in kOmega.C one term is devided by k. This is the reason why the minimum of k is SMALL.