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February 17, 2009, 10:30 
Hi all,
1.: I´m sure that s

#1 
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Andre Kunze
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Hi all,
1.: I´m sure that someone has already figured out how to calculate the electric field strength in openfoam and how to display it with paraview. I´d really appreciate if you could help me with that. 2.: I´m very new to Linux and OpenFoam and currently I´m running the virtual machine version of CAELinux2008 on Windows. So everything should be preinstalled and working, but when I type "wmake" in the console it always says "command not found". So at the moment I´m not getting further with figuring out on my own how to calculate the electric field strength because I can´t compile my own applications. Any idea on the second problem would be appreciated even more. Best regards André 

February 18, 2009, 04:58 
Update: Second problem solved.

#2 
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Andre Kunze
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Update: Second problem solved. Now to the first one...


February 18, 2009, 10:59 
which solver you are using now

#3 
Senior Member

which solver you are using now? i have i solver to solve the EHD problem.you can get electric field strenth in result, and the solver could be find in OpenFOAM wiki
Regards wayne 

February 18, 2009, 11:01 
The potential of an electrosta

#4 
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Mariam Winkler
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The potential of an electrostatic field is calculated using the poisson equation. I think there are examples in the userguide for this type of equation.
To my knowledge electrodynamics cannot be calculated with openfoam. What is your question about paraview display? Once you calculated the potential, write out it's gradient. Display the magnitude of this gradient, which is the field strength. Regards, Mariam 

February 18, 2009, 11:59 
Ok, finally I figured it out n

#5 
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Andre Kunze
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Ok, finally I figured it out now: I added the calculation of the gradient in the .H and .CFile of electrostaticFoam analogous to the rhoFlux calculation and compiled it. Now I have the electric field as a vector and the magnitude of it in paraview, which is what I wanted.
Salomé, OpenFOAM and paraview are nice tools if you have finally figured out how to work with them ;) Best regards André 

February 18, 2009, 12:07 
"To my knowledge electrodynami

#6 
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Andre Kunze
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"To my knowledge electrodynamics cannot be calculated with openfoam."
But it should be possible, shouldn´t it? Or is there already something in work perhaps? 

February 18, 2009, 13:08 
In order to solve electrodynam

#7 
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Michael Jaworski
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In order to solve electrodynamics problems, you have to solve the full Maxwell wave equations.
The programming guide does include the ability to put in second order time derivatives on page P37. This and a laplacian are all you need (provided you have the correct boundary conditions and EB coupling) to solve the wave equation. Alternatively, you only need the laplacian operator if you want to solve timeharmonic fields. c.f. Balanis, "Advanced Engineering Electromagnetics" John Wiley & Sons, 1989. or other suitable text on the topic. Regards, Mike J. 

February 19, 2009, 13:48 
Hm, something went wrong. I wa

#8 
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Andre Kunze
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Hm, something went wrong. I wanted to add this picture:


February 26, 2009, 09:04 
Hi all,
I have done a littl

#9 
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Andre Kunze
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Hi all,
I have done a little stepbystep guide about how to model a simple geometry and solve for its electric field in CAELinux. It´s written for absolute beginners like me. Would be nice if a real beginner could test it sometime and report back if everything worked out. stepbystep guide  part 1.pdf Best regards André 

February 26, 2009, 09:09 
And here is the second part:

#10 
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Andre Kunze
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And here is the second part: stepbystep guide  part 2.pdf


February 27, 2009, 02:20 
Andre and others,
I have

#11  
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Michael Jaworski
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Andre and others,
I have been looking at this capacitance calculation as well and I can't find a source for the discrepancy. I have constructed a much simpler mesh exploiting spherical symmetry and the solver I wrote calculates the field energy a little more simply using only: Quote:
I had also had a hunch that the problem might be numerical accuracy since the resultant energy is on the order of 10<sup>08</sup>. Rather than solve the phi equation the way it currently is in electrostaticFoam, I have: Quote:
The case that has been constructed is done with blockMesh (all files included below) and models a small wedge taken out of the sphere with arclengths of 5 degrees on a side. The bottom and top surfaces are constant phi surfaces (100 and 0) and the sides have a zeroGradient BC. I have used various levels of mesh refinement without much improvement from the results below. The energy/epsilon0 calculated for the case is 0.78461. Multiplying by 1650.1 scales the energy value from the wedge to full sphere and the calculated capacitance is 2.2926 pF. The analytical result is 2.2253pF, a difference of 3%. I have tried to go through various fvSolution tolerance levels (currently at 1e10) and fvSchemes but the solution never gets below a 3% error. So, is 3% error as good as this can get? Any thoughts on this matter would be greatly appreciated. Regards, Mike J. 

February 27, 2009, 02:29 
Andre and others,
I have

#12  
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Michael Jaworski
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Andre and others,
I have been looking at this capacitance calculation as well and I can't find a source for the discrepancy. I have constructed a much simpler mesh exploiting spherical symmetry and the solver I wrote calculates the field energy a little more simply using only: Quote:
I had also had a hunch that the problem might be numerical accuracy since the resultant energy is on the order of 10<sup>08</sup>. Rather than solve the phi equation the way it currently is in electrostaticFoam, I have: Quote:
The case that has been constructed is done with blockMesh (all files included below) and models a small wedge taken out of the sphere with arclengths of 5 degrees on a side. The bottom and top surfaces are constant phi surfaces (100 and 0) and the sides have a zeroGradient BC. I have used various levels of mesh refinement without much improvement from the results below. The energy/epsilon0 calculated for the case is 0.78461. Multiplying by 1650.1 scales the energy value from the wedge to full sphere and the calculated capacitance is 2.2926 pF. The analytical result is 2.2253pF, a difference of 3%. I have tried to go through various fvSolution tolerance levels (currently at 1e10) and fvSchemes but the solution never gets below a 3% error. So, is 3% error as good as this can get? Any thoughts on this matter would be greatly appreciated. Regards, Mike J. Solver files case files Mesh Image 

June 17, 2010, 19:50 
Electrostatic Foam

#13  
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Xingzhi You
Join Date: May 2010
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Hi Mike,
I get one question on the electrostatic foam, and hope you can give some thoughts and help. First, what is k in rhoFlux = k*mesh.magSf()*fvc::snGrad(phi) . I checked the dimension of it and: k [1 0 2 0 0 1 0 ] 0.00016 which means the unit is kg1· s2 ·A, this is not the electric conductivity unit as simens per meter would be m3·kg1·s3 ·A2. And we can restructure it to be (kg1S2A)(ASm3), and ASm3 is just Cm3(coulomb per cubic meter). It seems k is electric conductivity divided charge density, which makes it unknown to me. Furthermore,where does that weird 0.00016 come from, it is not any familiar constant or electric property. Second, in rhoFlux = k*mesh.magSf()*fvc::snGrad(phi) equation, the mesh.magSf() gives the magnitude of surface cell area. So rhoFlux would be, if not talk about the k, then surface area times potential gradient(at the surface normal, which is electric field), which gives: (electric_conductivity/charge_density)*(area)*(electric_field) = current/chargedensity This is so weird. Then what does solve fvm::ddt(rho) + fvm::div(rhoFlux, rho) means? Best regards, Hans Quote:


June 18, 2010, 03:55 

#14 
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Vincent de Graaf
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k is the ion mobility or electric mobility, which is defined by Vd=k*E. Vd is the drift velocity in m/s, k is the electric mobility and E the electric field strength. The drift velocity is the physical speed at which the charge carriers travel through the medium.
The unit of k is m^2/(Vs) which is equal to As^2/kg. 

June 21, 2010, 11:36 

#15  
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Xingzhi You
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Quote:


November 20, 2010, 09:12 

#16 
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Daniele
Join Date: Feb 2010
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Hi
I'm trying to use electrostaticFoam. I would use it to simulate an elctroforming cell to calculate Nickel deposit thikness. So I must calculate charge density on my cathode and from that I can obtain deposit thikness. But in electrostaticFoam I must impose rho on my cathode. Is this the correct way to solve my problem: 1) I Solve Laplace equation (I impose potential on my surface) 2) I compute electric field 3) I obtain charge density on my surface with Coulomb theorem: It's correct? Thanks 

November 14, 2015, 08:25 
how to calculate charge density ?

#17 
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Mieszko Młody
Join Date: Mar 2009
Location: POLAND, USA
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Dear Foamers,
I am trying to solve for electric potential inside the capacitor. But how can I calculate the charge density at the boundary ? Is the charge density zero, or nonzero value in between the capacitor plates ? thanks ZMM 

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