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August 24, 2005, 21:56 
hi Hrvoje Jasak,
I have a que

#1 
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Leosding
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hi Hrvoje Jasak,
I have a question in your phd thesis. In page 123, about Nonorthogonality error, it reads "For the complete diffusion term, the nonorthogonality error has the following form: E_d = \ Sigma _f S \ cdot [ ( \ rho U)_f K \ cdot (\ Nambla \ phi)_f] =\ Nambla \ cdot (\ Gamma_D \ cdot \ Nambla \ phi), where \ Gamma _D =(\ rho U)_f k. " I think in expresion $ E_d $ shoud get rid of "(\ rho U)_f" item, maybe "(\ rho \Gamma _\ phi)_f" which refers to Equation (3.24) in Page 83. Am I right? 

August 25, 2005, 08:37 
You are right  thank you very

#2 
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Hrvoje Jasak
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You are right  thank you very much.
I will try to rebuild the Thesis and put an updated version on my web site, but this might be quite painful. Thanks for the effort, I really appreciate it. Hrv
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August 25, 2005, 10:25 
Hi Hrv,
I have another questi

#3 
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Leosding
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Hi Hrv,
I have another question. In your PHD thesis page 145,equation(3.136) is $a_P U_P = H(U) \ Nambla p $, it is a semidiscretised form, it reads "It has been consequently divided through by the volume in order to enable face interpolation of the coefficients." So the expression of equation (3.136) is right. It means the item $\ Nambla p$ is derived from \ frac{\ int _V \ Nambla p dV}{V_P}=\ frac{(\ Nambla p)_P V_P}{V_P}. then refer equation(3.10) in page 79 and equation(3.26)in page 84, " $(\ Namble \ phi)_P = \ frac {1}{V_P} \ Sigma _f S \ phi_f$" but in page 146, equation(3.142) final form of discretised incompressible NS system for momentum equation is $a_P U_P = H(U)  \ Sigma_f S (p)_f $, it means the item $\ Nambla p$ in equation 145 is equal with $\ Sigma_f S (p)_f$, and this conflicts with equation(3.26), right? Maybe my understanding is wrong! Leosding 

August 27, 2005, 18:22 
I don't see what your problem

#4 
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Hrvoje Jasak
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I don't see what your problem is:
grad P discretises as: \grad \phi = \ frac {1}{V_P} \ Sigma _f S \ phi_f In order to discretise the momentum equation, I have to integrate over the CV, which brings in the volumes. So, if I want to interpolate the coefficients, I have to make them intensive and I divide the equation by the volume. Nothing tricky there... Hrv
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August 28, 2005, 08:12 
I know your mean.
My qustion

#5 
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Leosding
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I know your mean.
My qustion is(again): In order to discretise the momentum eqution, with integrate over the CV, you will gain the equation: A<sub>P</sub> U<sub>P</sub> = H<sup>'</sup>(U)+Ñp V<sub>P</sub> Equ(A); then wanting to interpolate the coefficients, you divide the equation Equ(A) by the volume V<sub>P</sub>, and get (3.136) in your thesis: a<sub>P</sub>U<sub>P</sub> = H(U)+Ñp; but the equation (3.142) is a<sub>P</sub>U<sub>P</sub> = H(U)+SS(p)<sub>f</sub>; Does it imply the Ñp = SS(p)<sub>f</sub>?( I think it's wrong, as of (3.26) in page 84,Ñf<sub>P</sub>=1/V<sub>P</sub>SSf<sub>f</sub>.) Of course, if equation (3.142) is from directly integrating (2.24) over the CV, it is right, then it imply the a<sub>P</sub> in (3.136) and (3.142) are different. If (3.142) is from (3.136), the item "SS(p)<sub>f</sub>" should be divided by "V<sub>P</sub>", right? Thank for your kindness to my stupid question. Leo 

August 28, 2005, 08:20 
Before you divide by the volum

#6 
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Before you divide by the volume you've got the volume integral of grad p which is equal to the sum_f S_f p_f.
After the division you have: aP UP = H(U)+ grad p; So: grad p = 1/V sum_f S_f p_f Hrv
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August 28, 2005, 09:44 
yes, the equation:
Ñp=1/V SS<

#7 
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Leosding
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yes, the equation:
Ñp=1/V SS<sub>f</sub> p<sub>f</sub> is RIGHT! but how did you derive to (3.142) from (3.136) directly? They are smae "a<sub>P</sub>" token in two equations. It's selfcontradicting from your thesis. 

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