Another discussion on velocity-pressure coupling -- CFD Online Discussion Forums

August 8, 2017, 03:51		#3
FMDenaro Senior Member Filippo Maria Denaro Join Date: Jul 2010 Posts: 6,779 Rep Power: 71	I am not sure about the actual key of the question, I have my opinion about the general issue: 1) first, we call pressure only a mathematical function that acts by means of a gradient. That has no physical meaning related to the classical action of the pressure. 2) if I multiply the momentum equation for the velocity vector field and integrate, the "pressure" disappears. In this sense, the pressure has no action on the velocity field. However, this is the classical weak form for which a possible solution is not necessarily unique. sbaffini likes this.

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